Geo. from GA asks this interesting question 'bout the propensity score: I was wondering whether replacing high dimensional covariates (X) in the regression model with their propensity scores (p(X)) was a good idea? That is, Y = a + bT + cX + e becomes Y= a + bT + c(p(X)) + e. The book does not really address it unless I missed it. What are the implications? Thanks.George: its certainly not a crazy idea. In fact, Dehejia-Wahba (1999) tried this (Table 5, estimates labeled quadratic in score). But its not clear what the theoretical justification is here; once you are using regression, why do this two-step procedure instead of just sticking the covs you've put in the score right into the reg (since you're implicitly assuming these are the only source of OVB)? Also, as we know from chpt 3, regression does not estimate the pop ATE or the effect of treatment on the treated except under constant effects or if the score is constant. Score fiends are often after those parameters instead of the variance-weighted avg that regression produces.
P-score in the reg?
Published March 27, 2010. Tagged Questions. Bookmark the permalink. Post a comment or leave a trackback: Trackback URL.
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